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Artist

  • ? jokanhiyou 1.3k

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  • ? san-x 304
  • ? touhou 951k

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  • ? fujiwara no mokou 27k
  • ? kiiroitori 40
  • ? rilakkuma 199

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  • ? 1girl 6.7M
  • ? animal costume 17k
  • ? bear costume 1.5k
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  • ? bow 1.3M
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  • ? math 1.2k
  • ? multiple views 197k
  • ? pink hair 802k
  • ? red eyes 1.4M
  • ? rilakkuma (cosplay) 22
  • ? simple background 2.1M
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Information

  • ID: 2706083
  • Uploader: 先男虫 »
  • Date: over 8 years ago
  • Size: 406 KB .jpg (908x837) »
  • Source: pixiv.net/artworks/62612414 »
  • Rating: General
  • Score: 8
  • Favorites: 17
  • Status: Active

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Resized to 93% of original (view original)
fujiwara no mokou, rilakkuma, and kiiroitori (touhou and 1 more) drawn by jokanhiyou

Artist's commentary

  • Original
  • 东方Project-藤原妹红

    这是一道送分题

    • ‹ prev Search: math next ›
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    NoNaku
    over 8 years ago
    [hidden]

    60

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    TonyGaiden
    over 8 years ago
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    25

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    darue
    over 8 years ago
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    15.

    The first three lines can be expressed as the coefficient matrix A = [3 0 0; 1 2 0; 0 1 2] with constant terms B = [30; 20; 9].

    Solving Ax = B for solution vector x yields:

    x = [10; 5; 2]

    The bottom line asks us to solve for n = x(2) + (x(3)/2)*x(1).

    Solving using the definition of x above yields:

    n = 5 + (2/2)*10

    n = 15

    Updated by darue over 8 years ago

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    DoubleT
    over 8 years ago
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    16

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    WingedIkaros
    over 8 years ago
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    Are we assuming that TwoBirds is the double of OneBird here? Because I don't see how this system implies such other than by visual representation of the variables, which should have no mathematical weight.

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    TonyGaiden
    over 8 years ago
    [hidden]

    WingedIkaros said:

    Are we assuming that TwoBirds is the double of OneBird here? Because I don't see how this system implies such other than by visual representation of the variables, which should have no mathematical weight.

    Oh, did not notice that, I guess that is the case

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    [deleted]
    over 8 years ago
    [hidden]

    [deleted]

    PhoenixG
    over 8 years ago
    [hidden]

    darue said:

    15.

    The first three lines can be expressed as the coefficient matrix A = [3 0 0; 1 2 0; 0 1 2] with constant terms B = [30; 20; 9].

    Solving Ax = B for solution vector x yields:

    x = [10; 5; 2]

    The bottom line asks us to solve for n = x(2) + (x(3)/2)*x(1).

    Solving using the definition of x above yields:

    n = 5 + (2/2)*10

    n = 15

    ok... mind is blown

    -1 Reply
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    thatThingYouAlwaysDo
    over 8 years ago
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    = 5 + 10x
    indeterminate because we have 4 unknowns but only 3 equations.

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    Kernel
    over 8 years ago
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    The answers are 5 ± 10√2. Because multiplication is the default when you don't specify the operator.

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    [deleted]
    over 8 years ago
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    [deleted]

    user 509825
    over 8 years ago
    [hidden]

    Paz_Legalces said:

    Wait a sec... why the heck everyone here giving fancy advanced maths solution, when this is just a usual equation meme popularly seen on Facebook?

    3BearMokou=30
    BearMokou=10

    10+2HeadMokou=20
    2HeadMokou=10
    HeadMokou=5

    5+2Chicks+2Chicks=9
    4chicks=4
    Chick=1

    HeadMokou+Chick+BearMokou =>10+5+1
    Final answer: 16

    Be aware that the math sign in the last row is a "*" and not a "+".
    So the last row is 5 + (1*10) = 15.

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    Paz Legalces
    over 8 years ago
    [hidden]

    Wait a sec... why the heck everyone here giving fancy advanced mathematics solution, when this is just the usual Equation Meme commonly seen on Facebook?

    3BearMokou=30
    BearMokou=10

    10+2HeadMokou=20
    2HeadMokou=10
    HeadMokou=5

    5+2Chicks+2Chicks=9
    4chicks=4
    Chick=1

    HeadMokou+Chick*BearMokou =>10+5*1 => 15

    provence said:

    Be aware that the math sign in the last row is a "*" and not a "+".
    So the last row is 5 + (1*10) = 15.

    Dammit, noticed that error and deleted my previous comment in less than 20 seconds ago, but it was a tad late it seem

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    Type-kun
    over 8 years ago
    [hidden]

    Paz_Legalces said:

    Wait a sec... why the heck everyone here giving fancy advanced mathematics solution, when this is just the usual Equation Meme commonly seen on Facebook?

    Coefficient matrix solution is just a fancy (and compact, at least on paper) way to solve multiple equations; math is actually exactly the same to what you described - notice how vector x has the same values as your variables :3

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    lkfwks
    almost 8 years ago
    [hidden]

    19.1421356237...
    My reasoning: In the one above, we have a symbol that is "chick and chick"
    There is no operator between them in each pair of chicks, so logically if chick is a symbol of its own, then it is undefined or it is the square root of "chick and chick" Since we're clearly going after the premise that the one chick has been defined, then it's the latter, thus the chick is the square root of 2. So it's 5+1.41421356237...*10
    Multiplication first and you have 5+14.1421356237...
    The result is 19.1421356237...

    Updated by lkfwks almost 8 years ago

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    Cliff Edge
    over 7 years ago
    [hidden]

    42.

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    [deleted]
    almost 6 years ago
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    [deleted]

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