I'm not one to do math but if an admiral is the average weight of a healthy japanese male and Amatsukaze weighs at least 2,490 long tons....

ThatOneDudeLooking said:

I'm not one to do math but if an admiral is the average weight of a healthy japanese male and Amatsukaze weighs at least 2,490 long tons....

I am one to do math!

Quick google gives us the average weight of a Japanese adult male as 62.5 kg. So the equation is 62.5 kg * x m = 2033000 kg * 1.5 m. Solve for x, that gives us...

48,792 meters. That's just under 50 kilometers, or about 30.3 miles.

What tensile strength of material a 30-mile-long seesaw would need to not snap under its own weight (much less the weight of a warship on one end), and how far short modern construction materials fall from being strong enough, is left as an exercise for someone even more physicsy than myself.

Of course, that is impossible. You would be accounting for millions of newton meters in torque and rotational force on that single point.

The only thing that we have that I think might be capable of such a feat would be graphene plate, but the see-saw would have to be quite thick, not to mention the technology itself is nowhere near the point of being able to make such a thing.

I can see why she's secretive about her weight; it can be measured in gigagrams.

This seems to be a followup to a question he posted earlier.

Mithiwithi said:

I am one to do math!

Quick google gives us the average weight of a Japanese adult male as 62.5 kg. So the equation is 62.5 kg * x m = 2033000 kg * 1.5 m. Solve for x, that gives us...

48,792 meters. That's just under 50 kilometers, or about 30.3 miles.

What tensile strength of material a 30-mile-long seesaw would need to not snap under its own weight (much less the weight of a warship on one end), and how far short modern construction materials fall from being strong enough, is left as an exercise for someone even more physicsy than myself.

I got 50.83Km but I rounded the 9.8 up to 10 for ease of calculation and figures. Either way that's a seriously long seesaw, and an extremely dense girl.

Dinamus said:

I got 50.83Km but I rounded the 9.8 up to 10 for ease of calculation and figures. Either way that's a seriously long seesaw, and an extremely dense girl.

The force of gravity cancels out provided it's the same on both sides of the seesaw.

The real flaw is that I (and I suspect you) was ignoring the mass of the seesaw. I used to know the formula for the moment of inertia of a uniform-density shaft, but I've forgotten. But either way, the answer would depend on the mass per meter of the seesaw, and I don't know the density of scrith anyway.

All I can say for sure is that the actual length of the seesaw on the Japanese male's side would be substantially less because more of the seesaw is on his side. And that I'm pretty sure that there is no material substance available to present-day materials science that has the tensile strength to serve as the seesaw or the compressive strength to serve as the fulcrum.